Multiply and Simplify...
y^2-16/y^2+8y+16*3y^2-5y-2/y^2-6y+8
3y+1/y+4
Am I on the right track?
2007-07-30 12:59:54 · 3 answers · asked by Jacesmom 2 in Science & Mathematics ➔ Mathematics
(y^2-16)/(y^2+8y+16) * (3y^2-5y-2)/(y^2-6y+8) =
1. factor polynomials
(y-4)(y+4)/(y+4)(y+4) * (3y+1)(y-2)/(y-4)(y-2) =
2. simplify
(y-4)/(y+4) * (3y+1)/(y-4) =
3. multiply
(y-4)(3y+1)/(y+4)(y-4) =
4. reduce
(3y+1)/(y+4)
2007-07-30 13:11:55 · answer #1 · answered by D J 3 · 0⤊ 0⤋
y^2-16/y^2+8y+16*3y^2-5y-2/y^2-6y+8
[(y^2-16)/(y^2+8y+16)]*[(3y^2-5y-2)/(y^2-6y+8)]
= [(y-4)(y+4)/(y+4)^2]*[(3y+1)(y-2)/(y-2)(y-4)]
= [(y-4)/(y+4)]*[(3y+1)/y-4)]
=(3y+1)/(y+4)
Ypu are absolutely on the right track. In fact you have sucessfully pulled into the station.
2007-07-30 20:14:56 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
can i go to the toilet please sir
2007-07-30 20:19:14 · answer #3 · answered by Anonymous · 0⤊ 1⤋