Determine the heat of reaction for the decomposition of one mole of benzene to acetylene?

Question

Determine the heat of reaction for the decomposition of one mole of benzene to acetylene C6H6(l)-->3C2H2(g) given the following thermochemical equations:

2C6H6(l)+15O2(g)-->12CO2(g) + 6H2O(g) Delta H = -6271kj
2C2H2(g)+ 5O2(g)-->4CO2(g) 2H2O(g) Delta H = -2511kj

Answer 1

Half the first value minus 1.5 x the second value.

Answer 2

2C6H6(l)+15O2(g)-->12CO2(g) + 6H2O(g) Delta H = -6271kj *label this equation, A
2C2H2(g)+ 5O2(g)-->4CO2(g) 2H2O(g) Delta H = -2511kj *label this equation, B
C6H6(l)-->3C2H2(g) *label this equation as C

A= *1/2 delta H= -627*1/2
B= reverse * (3/2) delta H=2511 (3/2)
C = delta H= 631 KJ

Answer 3

The answer is "meat".