2007-07-30 10:22:52 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(√2 - 3) (√2 + 3) = 2 - 9 = - 7
2007-07-30 10:37:40 · answer #1 · answered by Como 7 · 1⤊ 0⤋
First, foil the expression.
(sqrt2 - 3)(sqrt2 + 3)
2 + 3(sqrt2) - 3(sqrt2) - 9
3(sqrt2) - 3(sqrt2) cancel each other out. So you're left with 2 - 9 =
-7
2007-07-30 10:28:48 · answer #2 · answered by Jae 3 · 0⤊ 0⤋
sqrt2 * sqrt2 = 2
sqrt2 * 3 = 3 * sqrt2
sqrt2 * -3 = -3 * sqrt2
3 * -3 = - 9
//add them up
( 2 ) + (3*sqrt2) + (-3sqrt2) + (-9) =
//the middle terms cancel out since they are equal but opposite terms.
( 2 ) + (-9 ) =
//simple addition gives us...
-7
2007-07-30 10:32:09 · answer #3 · answered by Joe 4 · 0⤊ 0⤋
(sqrt2 - 3)(sqrt2 + 3) =
sqrt2*sqrt2 - 3*sqrt2 + 3*sqrt2 - 9 =
2 - 9 =
-7
First you multiply it out.
A square root multiplied by the same square root is equal to the number inside.
The positive and negative 3*sqrt2 cancel out.
2007-07-30 10:30:44 · answer #4 · answered by Chase Utley 2 · 0⤊ 0⤋
(sqrt2 - 3)(sqrt2 + 3)
= [(sqrt2)^2 - 3^2]
= (2 - 9)
= -7
2007-07-30 10:26:53 · answer #5 · answered by fofo m 3 · 0⤊ 0⤋
(sqrt2 - 3)(sqrt2 + 3)
= 2-9 ....diff of 2 sqs
= -7
2007-07-30 10:26:57 · answer #6 · answered by harry m 6 · 0⤊ 0⤋
this is of the form (a-b)(a+b)
now, (a-b)(a+b) = a^2 - b^2
so, (sqrt2 - 3)(sqrt2 + 3) = (sqrt2)^2 - (3)^2
= 2 - 9
= 7
_______________
2007-07-30 10:27:49 · answer #7 · answered by Vipin A 3 · 0⤊ 0⤋
sqrt2*sqrt2+3sqrt2-3sqrt2-9
2-9=-7
doesn't look like it needs a radical if you copied the question correctly
2007-07-30 10:30:19 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(?3+?5)(?3+?5) your improve is faulty each and each term interior the 1st bracket might desire to be prolonged to each and each term interior the 2d with the aid of increasing (3+?15+?15+5) word: ?5 x ?3 = ?15 consequently =(8+2?15) if extra simplification is important =(8+?60)
2016-10-13 03:22:40 · answer #9 · answered by coiscou 4 · 0⤊ 0⤋
sqrt4times-9
2007-07-30 10:29:47 · answer #10 · answered by Bonnie R 2 · 0⤊ 0⤋