A few math qustions I am stuck on. Yahoo Answers community come on and help me out, PLEASE!!!?

Question

1. Find the slope of the line that passes through the points (2, 3) and (5, 8).




2. Find the equation of the line that passes through the points (3, -2) and (4, -2).




3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 3y = 6 and passing through (-3, 5).

1. Simplify and evaluate:
(42x3y-2z-3/x-5y8z-9)2




2. Convert to scientific notation (here you may use x as multiplication):
0.00083




3. For f(x) = 6x – 7, find f(2).




4. Perform the indicated operations:
(-x2 – 6x + 3) – (-9x2 + x – 1) – (x2 + 5x – 2)




5. Use FOIL to multiply:
(8x – 1)(2x + 5)




6. Multiply:
(x4 – 4x2 – 5)(x2 – x + 2)

Thank you so much in advance. I know there are alot of math whizs out here much smarter than me. Please help me out, much love and appreciation!

Answer 1

1)slope = (8-3)/(5-2) = 5/3 = 1 2/3.

2)slope = (-2--2)/(4-3) = 0/1 = 0.
SO, plug 1 of points in y=mx+b.
-2=(0*3)+b. So, b=-2.
So, equation is y=-2.

3)Find slope of x+3y=6.
3y=-x+6, so y=(-1/3)x+2.
So, slope is (-1/3), so perpendicular slope
is -1/(-1/3) = 3.

SO, put in y=mx+b and plug in (-3,5).
SO, 5=(-3*3)+b, so b=14.
SO, equation is y=3x+14.

1) Not sure?

2)8.3*10^-4

3)f(2) = (6*2)-7 = 5

4)7x^2-12x+6

5)16x^2+40x-2x-5 = 16x^2+38x-5

6)x^6-x^5+2x^4-4x^4+4x^3-8x^2

-5x^2+5x-10 =
x^6-x^5-2x^4+4x^3-13x^2+5x-10.

Check for mistakes on last one!

Answer 2

1. slope = (y2-y1)/(x2-x1) = (8-3)/(5-2) = 5/3
2. (3, -2) and (4, -2). This has a slope of 0 since y2=y1.
So the equation is simply y= 0*x -2 --> y= -2
3. line perpendicular to x + 3y = 6 and passing through (-3, 5).
Slope of line x+3y=6 is -1/3 so slope of line perpendiular to it is -1/(-1/3) = 3. so equation is y=3x+b. 5=3(-3)+b, so b =14.
Thus the equation is y=3x+14.
1. (42x3y-2z-3/x-5y8z-9)2 Sorry, but this is ambiguous and can be interpreted in too many different ways. Please learn how to use paretheses properly and how to indicate exponentiation.
2. 0.00083= 8.3 X 10^-4 [^ means exponentiation]
3.f(x) = 6x – 7, find f(2). Simply replace x with 2 getting:
f(2) = 6(2) - 7 = 12-7 = 5
4. (-x2 – 6x + 3) – (-9x2 + x – 1) – (x2 + 5x – 2)
= -x^2 -6x +3 +9x^2 -x +1 -x^2 -5x +2 = 7x^2-12x+6
5.(8x – 1)(2x + 5)= 16x^2 +40x-2x -5 = 16x^2 +38x -5
6.(x4 – 4x2 – 5)(x2 – x + 2)
= x^6 -x^5-2x^4+4x^3-13x^2+5x-10

Answer 3

That is just a few questions..
If you are struggling with this you should try to find someone to explain it to you. This is very basic and you will need to know it for other required math courses.

Answer 4

1)5/3
2)y=-2


3)5
4)7x^2-12x+6
5)16x^2+38x-5
6)u'r turn