2007-07-30 08:09:37 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2z² - 5z + 2 = 0
(2z - 1)(z - 2) = 0
z = 1 / 2 , z = 2
2007-07-30 08:41:51 · answer #1 · answered by Como 7 · 1⤊ 0⤋
You need to move the -2 and the 5z to the other side. Add 2 and subtract the 5z (because the 2 is negative and the 5 is positive so you must do the opposite to move them) you end up with 2z^2 -5z + 2 =0. Then you need to unfoil it. Basically it is going to look like this when you're done. ( ) ( ). I won't do the whole problem for you but hopefully this will give you a start.
2007-07-30 15:15:52 · answer #2 · answered by Carolyn D 5 · 0⤊ 1⤋
Get 0 on one side first:
2z^2 - 5z + 2 = 0.
Factor:
(2z - 1)(z - 2) = 0
Set each factor = 0 and solve:
z = 1/2, z = 2
2007-07-30 15:11:44 · answer #3 · answered by jenh42002 7 · 0⤊ 0⤋
Get everything on one side:
2z^2-5z+2=0
Then factor it...
2007-07-30 15:15:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2z^2 = -2 + 5z
2z^2 -5z + 2 = 0
[5 +- Sq Rt (25 - 16)]/4
(5 +- 3)/4 = 0
z = 2
z = 1/2
2(z - 2) (z - 0.5) =
2(z^2 - 2.5z + 1) =
2z^2 - 5z + 2
2007-07-30 15:20:33 · answer #5 · answered by robertonereo 4 · 0⤊ 1⤋
z = [-1 + (5/2)z] ^ 1/2
2007-07-30 15:13:32 · answer #6 · answered by baby girl 2 · 0⤊ 0⤋
Do your own homework
2007-07-30 15:11:24 · answer #7 · answered by ♡LiL♥Kitten♡ 5 · 0⤊ 0⤋