find the dimensions
2007-07-30 05:08:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16, 64
Call the short side x
Call the long side 4x
There are two long and two short sides. All together they add up to 160. This gives:
2x + 8x = 160
x = 16
4x = 64.
Hope that helps.
2007-07-30 05:11:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Length = 4width
Hence the rectangle consists of 2 lengths (8 widths) + @ widths
Total 10 widths.
160/10= 16yds
length= 4 width: length= 64yds
width=16
2007-07-30 12:14:49 · answer #2 · answered by Robert M 3 · 0⤊ 0⤋
Let l = the length and w = the width.
l = 4w
2l + 2w = 160
Solve using substitution:
2(4w) + 2w = 160
8w + 2w = 160
10w = 160
w = 16
And since the length is four times the width, the length will be 64 yards.
So the answer is length = 64 yards, width = 16 yards
2007-07-30 12:14:36 · answer #3 · answered by Benjamin K 2 · 0⤊ 0⤋
2w + 2 * 4w = 160, so 10w = 160, and w = 16
so width = 16, and length = 64
2007-07-30 12:13:56 · answer #4 · answered by John V 6 · 0⤊ 0⤋
l = 4w
2l + 2w = 160
l + w = 80
w + 4w = 80
5w = 80
w = 16, l = 64
2007-07-30 12:12:58 · answer #5 · answered by A M Frantz 7 · 0⤊ 0⤋