can you please solve theses inequality's if posible
1. -2 > 5 + y
2. /j-7/ - 1 < 3 5/6
3. /3y + 1/ - 6 = -2
2007-07-30 04:48:24 · 4 answers · asked by sailorsoccer07 1 in Science & Mathematics ➔ Mathematics
1. Just subtract 5 from both sides to get y by itself.
Ans. y < -7
2. Add one to both sides to get |j-7| < 4 5/6. Now note that if the absolute value of j-7 is less than 4 5/6, then j-7 by itself has to be less than 4 5/6 and greater than -4 5/6.
In other words: -4 5/6 < j-7 < 4 5/6
Now add 7 to both sides.
Ans. 3 5/6 < j < 11 5/6
3. Add 6 to both sides to get |3y+1| = 4
Now in order for that to be true, 3y+1 has to be equal to positive or negative 4. So set those two equations up and solve for y.
Ans. y = 1 or -5/3
2007-07-30 04:59:17 · answer #1 · answered by Benjamin K 2 · 0⤊ 0⤋
1) y > -7
2007-07-30 11:54:46 · answer #2 · answered by Grant d 4 · 0⤊ 1⤋
1. -2 > 5 + y
y < - 7
2007-07-30 11:55:22 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
?what is there to solve?
2007-07-30 11:51:03 · answer #4 · answered by <3Vasudha Loves Yhu(; 3 · 0⤊ 1⤋