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Picture included of rhombus/units
2007-07-30 03:25:07 · 7 answers · asked by Adrienne W 1 in Science & Mathematics ➔ Mathematics
Area = (1/2)( 4 x 10 )cm ²
Area = 20 cm ²
2007-07-30 23:04:34 · answer #1 · answered by Como 7 · 1⤊ 0⤋
The diagonals of a rhombus intersect at 90 degree angles.
So, you can find the area of one of those triangles and then multiply by 4.
Area (triangle) = (1/2)(5)(2) = 5
Area (rhombus) = 4(5) = 20
2007-07-30 03:28:48 · answer #2 · answered by Mathematica 7 · 0⤊ 1⤋
the most simple approach to this problem is using the formula A = (1/2) (d1)(d2), where d1 and d2 are the lengths of both diagonals.
Sind the diagonals of all parallelograms bisect each other, then the diagonals for this rhombus are 4 units and 10 units longs.
So the area of this rhombus is half the product of 4 times 10, which is 20.
Therefore the area of this rhombus is 20 square units.
Although others who posted offered varying approaches to this problem, I hope the one I offered helped also.
Remember, Area of a rhombus = (1/2)(d1)(d2).
:-)
2007-07-30 03:46:32 · answer #3 · answered by apodosis 2 · 0⤊ 1⤋
I think the easiest way is to just turn it into 2 rectangles. Each rectangle has an area of (2 * 5) = 10, so 2 of these rectangles have an area of 20.
2007-07-30 03:29:20 · answer #4 · answered by Chas D 2 · 0⤊ 1⤋
4[(1/2)(5)(10)]
= 20 cm^2
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Reason: The rhombus consists of four congruent right triangles with each area = (1/2)(5)(10) cm^2.
2007-07-30 03:28:43 · answer #5 · answered by sahsjing 7 · 0⤊ 0⤋
area=1/2*10*4=20cm^2
2007-07-30 03:37:37 · answer #6 · answered by Anonymous · 0⤊ 1⤋
25x4=100
2007-07-30 03:45:20 · answer #7 · answered by Anonymous · 0⤊ 1⤋