Find the missing diagonal of the rhombus that has an area of 12 feet squared and one diagonal of 6ft.?

Question

Find the missing diagonal of the rhombus that has an area of 12 feet squared and one diagonal of 6ft.

Answer 1

Although most people use (base)(height) to calculate area, you can also use (1/2)(product of diagonal lengths) for area of rhombii also.

start with, A = (1/2)(d1 * d2)
..............12 = (1/2)(6 * d2)
therefore d2 = 4


So the missing diagonal of this rhombus is 4 feet long.

Hope this helps! :-)

Answer 2

Area of rhombus = half the product of the diagonals

A =1/2 d1 X d2
So 12=1/2 (6 X d2)
Multiply both sides of the equation by 2 to get rid of the 1/2
24=6 X d2
Divide by 6 to get d2 on its own
4 = d2
Therefore the missing diagonal measures 4 feet

Answer 3

the ans. is 4 feet
you have to make use of the property of the rhombus which states that the diagonals bisect each other at right angles.So when diagonals bisect 4 congruent right angled triangle is formed
area of each triangle = 0.5*3*x
where x is half of the other diagonal
there fore total area of rhombus is 0.5*3*4*x =12
that is 6x=12
x=2
therefore length of other diagonal is 4 feet