Find the area of a rhombus with diagonals of 4 feet and 5 feet.
2007-07-30 03:09:04 · 5 answers · asked by zerokun4 1 in Science & Mathematics ➔ Mathematics
10 sq. ft.
Just multiply the diagonals and divide by 2
A_rhombus = 1/2 * d_1 * d_2
This is easily proven when you realize that a rhombus is simply four congruent right triangles whose right angles form a common point.
Actually, this equation will work for any deltoid... proven with just a little more algebra than for a rhombus.
2007-07-30 03:12:37 · answer #1 · answered by Anonymous · 2⤊ 1⤋
The area of a Rhombus is half the product of the diagonals.
Area = (½) d1d2
A=1/2 X 4' X 5'
=1/2 X 20 sqare feet
= 10 square feet
2007-07-30 10:17:20 · answer #2 · answered by crrllpm 7 · 1⤊ 0⤋
Area of a Rhombus =1/2(d1 x d2)
= 1/2(4 x 5)
=10 sq feet
= 0.929 cm²
2007-07-30 10:51:46 · answer #3 · answered by Anonymous · 1⤊ 1⤋
A = (1/2) x 4 x 5 ft²
A = 10 ft²
2007-08-03 02:01:30 · answer #4 · answered by Como 7 · 1⤊ 0⤋
(1/2)(4)(5) = 10
The area of a rhombus is half the area of the rectangle that it fits inside.
2007-07-30 10:15:04 · answer #5 · answered by Scythian1950 7 · 1⤊ 1⤋