The diagonals of a square each measure 7 feet. Find the area of the square.?

Question

The diagonals of a square each measure 7 feet. Find the area of the square.

Answer 1

Area of a square = (1/2)d^2 where d is the length of the diagonal

Area = (1/2)*7^2
= 24.5 square feet

Answer 2

a million)If the fringe is 36 inches, then, divided by potential of four, the facets could be 9 inches each and every. Now, to discover the section, you in basic terms sq. the facets: 9² = 80 one the section is 80 one inches² ======================== 2)For the rectangle, you will observe it has 2 gadgets of equivalent facets. permit x be the width of the rectangle you're searching for: x + x + 7 + 7 = 35 2x + 14 = 35 2x = 21 x = 10.5 The width is 10.5cm ======================== 3)permit the facets of the sq. be x (all facets of a sq. is equivalent). utilising Pythagoras (notice that the diagonal creates a real-angled triangle): x² + x² = 7² 2x² = 40 9 x² = 24.5 x = ?24.5 So the facets are ?24.5 ft each and every. To get the section, sq. the facets: (?24.5)² The squareroot and the ² cancel out, leaving 24.5 Your section is 24.5 ft²

Answer 3

If the diagonal measures 7 feet, then the sides each measure (7 / sqrt 2) feet.

Area = (7 / sqrt 2)(7 / sqrt 2) = 49 / 2 = 24.5 sq ft.

To find the measure of the side, use pythagorean theorem.
7^2 = s^2 + s^2
49 = 2 s^2
49 / 2 = s^2
7 / sqrt 2 = s

Answer 4

the diagonal forms a right triangle, and so 7^2 = 49 = 2s^2, so s^2 = 49/2 = 24.5 sq ft. = area.

Answer 5

Let length of side = x ft
7² = x² + x²
2x² = 49
x² = 49 / 2
Area of square = x²
Area of square = 49 / 2 ft² = 24.5 ft²

Answer 6

49