5 ways
2007-08-06 18:27:19
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answer #1
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answered by Anonymous
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48
It might first appear that you can simply do 5 * 2^4 (note to thengine7, 2^4 = 16, not 8) and get 80, because you have HHH**** *HHH*** **HHH** ***HHH* and ****HHH. This is incorrect because by filling in all possible combinations of heads and tails for the *s you count both HHH(h)*** and (h)HHH***, even though they are the same.
How do we fix this? well, for every instance of HHHH, we want to remove 1 from our previous total of 80. By using the above method with four heads instead of 3 we get 4 * 2^3 = 32. There will be repeats here as well ( HHHH(h)** and (h)HHHH**) but this is ok, in fact, it saves us some time. In a group of 5 heads 4 heads will count twice, and 3 heads will count thrice. Thus subtracting our total will remove repeats for occurances of 4, and 5 heads in a row. If you try this with 6 and 7, you will see that it works there as well.
So, we take 80, remove the duplicates ( - 32) and are left with 48 occurances of 3 consecutive heads.
note: vishal, even though that isn't what the question asked, your answer is still wrong.
edit: mith, your stupidity doesn't make my answers "off the wall" HHHTTTT and HHHTHTT are two different ways that 3 consecutive heads can be obtained... understand yet genius?
2007-07-30 06:22:11
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answer #2
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answered by Benjamin H. 2
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5
2007-07-30 05:43:59
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answer #3
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answered by Anonymous
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The above poster is near correct, if you got HHH , you then have 8 different outcomes you don't care about, from 4 more tosses. 2^4 = 8
That also means that there are 4 more positions where you can have the 3 consecutive tosses happen. so thats 8 outcomes times 5 different positions = 40 different ways.
5 total positions.. HHHTTTT, THHHTTT, TTHHHTT, TTTHHHT, TTTTHHH. the tails can be heads or tails, we don't care.
2007-07-30 05:44:48
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answer #4
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answered by thengine7 2
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ANS:5/128
Probability of getting a HEAD = 1/2
Probability of getting a TAIL = 1/2
Probability of getting 3 HEAD in 3 attempts =1/2 * 1/2 * 1/2
= 1/8
Probability of getting 3 HEAD in 4 attempts
=1/8 *1/2+ 1/2*1/8
=2 * ( 1/8 * 1/2 )
= 1/8
similarly....
Probability of getting three consecutive HEADS in 7 attempts
= 5 * (1/8 * 1/16)
= 5/128
2007-07-30 05:47:53
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answer #5
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answered by VISHAL A 2
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I agree that their are 5 ways. I don't know what the others were doing. There off the wall answers made me spend alot of time trying to figure out what they were thinking (I never did).
2007-08-05 08:03:40
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answer #6
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answered by mith 2
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Tosses
1,2,3
2,3,4
3,4,5
4,5,6
5,6,7
There are 5 ways
2007-08-04 16:01:03
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answer #7
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answered by Como 7
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