A car of mass 1000 kg is being towed on level ground by a van of mass 2000 kg. There are constant retarding forces (due to air resistance and friction) on both the car and the van. The car force on the car is 300 N; on the van it is 500 N.
1) What is the size of the force due to the van's wheels that pushes the van forwards?
2) What is the size of the tension T in the towbar?
3) When the two vehicles are travelling at 15 m/s, the van driver disconnects the motor from the driving wheels, and the van and the car slow down at a constant rate due to the constant retarding forces acting on the vehicles. How far do the two vehicles travel before coming to rest?
Can u explain it so I understand it? Thanks!
2007-07-29 22:07:27 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
1. Assuming constant speed so there is no acceleration, then the van must pull enough to overcome the sum of the forces of 800 N.
2. The tension in the tow bar is the resisting force of the car of 300 N.
3. For this I will use conservation of energy. The starting kinetic is the sum of the masses times .5 times the square of the velocity or
1500*15^2
and the work done will be the resistance of the friction and air
Assuming a constant deceleration
800*d=1500*15^2
d=422 m
j
2007-07-30 05:59:56 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
F=800N
T=300N
800= 3000a then a =800/3000= 4/15 m/s^2
V^2=Vo^2 +2 a S
0= (15)^2-2 (4/15)S then S = 421.875m
2007-07-31 03:24:55 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
yet my philosophy says rigidity dene ka nahi lene ka, khushiya lene ka nahi dene ka you will constantly experience greater effective, none can b happy with the aid of giving rigidity different except giver is evil...
2016-10-13 02:21:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋