2007-07-29 17:55:20 · 5 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics
x*(x-6) = x-12
==> x^2 - 6x = x - 12
==> x^2 - 6x -x + 12 = 0
==> x^2 - 7x + 12 = 0
==> (x-3)(x-4) = 0
==> x = 3 or x = 4
2007-07-29 17:58:14 · answer #1 · answered by Jeƒƒ Lebowski 6 · 1⤊ 0⤋
x(x - 6) = x-12
x^2 - 6x = x - 12
x^2 - 6x - x + 12 = 0
x^2 - 7x + 12 = 0
(x - 4)(x - 3) = 0
x - 4 = 0 or x - 3 = 0
x = 0 + 4 or x = 0 + 3
x = 4 or x = 3
Therefore, x = 4 or 3.
=^-^=
2007-07-30 05:06:35 · answer #2 · answered by in 30mins 3 · 0⤊ 0⤋
X=4
X=3
2007-07-30 00:59:44 · answer #3 · answered by *<3* 1 · 0⤊ 0⤋
x² - 6x = x - 12
x² - 7x + 12 = 0
(x - 4) (x - 3) = 0
x = 3 , x = 4
2007-07-30 05:39:28 · answer #4 · answered by Como 7 · 0⤊ 0⤋
The answer is purple!?
2007-07-30 01:03:00 · answer #5 · answered by tincerbell101 3 · 0⤊ 0⤋