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A horizontal trough with semicircular cross sections 5 feet in diameter contains oil with a weight density of 80 lb/ft^3. If the trough is 25 feet long and filled with oil to a depth of 3 feet, find the work required to pump all of the oil to the top of the tank?

2007-07-29 17:00:06 · 2 answers · asked by shortdude 2 in Science & Mathematics Mathematics

2 answers

∫(80)(1/2)pi(5/2)^2(25-y)dy, y from 0 t0 3
= 55,370.57 lb*ft

2007-07-29 17:43:11 · answer #1 · answered by sahsjing 7 · 0 0

The top of which tank? You've described a trough. What does the tank have to do with it?

2007-07-29 17:04:26 · answer #2 · answered by TychaBrahe 7 · 0 0

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