1. 16y2 - 8y + 1 = 0
2. c2 + 10c - 25 = 0
3. 5x2 + 8x + 16 = 0
4. a2 - 5a - 14 = 0
5. If a quadratic does not have a linear term (in other words it is a "pure quadratic"), then it will always have 2 real solutions.
true or false?
2007-07-29 16:19:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(4y - 1)^2
(c - 5)^2
(5x + 8)(x + 2)---------. this problem should have read,
5x^2 + 18x +16
(a - 7)(a + 2)
false, the answer could be zero, or only 1 solution
2007-07-29 16:23:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
5. False.
1. (1-4y)^2
2. (c+5)^2
3. Do quad formula
4. (a-7)(a+2)
2007-07-29 23:28:20 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
use the quadratic equation
[- b plus or minus sqrt(b^2 -4ac) ] / 2a
where a b and c are the coefficients of the 2nd degree term, 1st degree term, and constant
2007-07-29 23:22:42 · answer #3 · answered by superman 4 · 0⤊ 0⤋