2007-07-29 16:18:49 · 5 answers · asked by theblueyoshi 2 in Science & Mathematics ➔ Mathematics
this vector can be written < -4, 12> the formula to find magnitude for vector is, example we have vector
then mag = squareroot( a^2+b^2)
in this problem a=-4, b=12
therefore mag = squareroot( {-4}^2 +12^2)
mag = sqrt( 16+144)=sqrt(160)= sqrt( 16*10)
= 4sqrt(10)
good luck
2007-07-29 16:37:00 · answer #1 · answered by Helper 6 · 1⤊ 0⤋
magnitude (or norm) of the vector xi + yj isâ( x^2 +y^2)
then magnitude of the given vector is â 16+144= â 160=4â10
2007-07-30 11:36:58 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
Oops, I think Mr. Saunders had a typo. the magnitude should be....
sqrt(4^2 + 12^2).
2007-07-29 23:38:24 · answer #3 · answered by mathgoddess83209 3 · 0⤊ 0⤋
4 is horizontal component (-ve sign indicates "to left")
12 is vertical component (upwards)
magnitude = r , say
r² = 4² + 12²
r² = 16 + 144
r² = 160
r = 4â10
2007-07-31 11:30:45 · answer #4 · answered by Como 7 · 0⤊ 0⤋
Pythagoras rides again; it is simply sqrt(4^2 + 12*2).
2007-07-29 23:22:13 · answer #5 · answered by Anonymous · 0⤊ 0⤋