A heating element in a stove is designed to dissipate 2600 W when connected to 240 V. Assuming that the resistance is constant, calculate the current in this element if it is connected to 120 V.
How do I solve this? Thanks in advance.
2007-07-29 14:27:27 · 4 answers · asked by protege moi 3 in Science & Mathematics ➔ Physics
current is in amps.
and to the jerkoff: sorry i don't understand physics and my book doesn't match up with the professors.
2007-07-29 14:34:30 · update #1
I FIGURED IT OUT you all suck.
2007-07-29 14:43:23 · update #2
The current in the heater when 240 v is applied is Power / p.d
2600 / 240 =10.83 A
The resistance of the heater is P.d / current = 240 / 10.83 = 22.16 ohm.
When this is connected to 120 V, the current is[ P.d/ Resistanc]
=120 / 22.16 = 5.415 A
2007-07-29 22:50:07 · answer #1 · answered by Pearlsawme 7 · 0⤊ 0⤋
Power measured in Watts (W) = voltage X amperage.
If the resistance is constant then the voltage will remain the same on a 240 v circuit or a 120 v circuit; as listed. The only variable will be the amperage.
2600 w = 240 v X Amp => 2600/240 = 10.8333 amps.
2600 w = 120 v X Amp => 2600/120 = 21.6667 amps.
2007-07-29 21:33:16 · answer #2 · answered by Dan S 7 · 0⤊ 3⤋
Do your own homework. Nobody can work for you, ok?
2007-07-29 21:30:52 · answer #3 · answered by John 2 · 1⤊ 2⤋
v x c=w,so1300w
2007-07-29 21:30:59 · answer #4 · answered by Anonymous · 0⤊ 2⤋