solve algrbraically:
x3/2=27
2007-07-29 12:56:10 · 13 answers · asked by quepid622 1 in Science & Mathematics ➔ Mathematics
well u have to isolate x
so it will be 27 divided by 3/2
27/1 divide 3/2
= 27 *2/3
=54/3=18
x = 18
2007-07-29 12:59:38 · answer #1 · answered by tochau 5 · 0⤊ 0⤋
x = 18
2007-07-29 12:59:08 · answer #2 · answered by whiteness 3 · 0⤊ 0⤋
x=18
2007-07-29 12:59:56 · answer #3 · answered by ycartf 2 · 0⤊ 0⤋
If that is supposed to be x times 3 divided by 2, then x = 18.
If it is supposed to be x to the 3/2 power, then x = 9.
x * 3/2=27
X*3 = 54
X = 18
X^(3/2) = 27
Square both sides so X^3 = 729
Cube root of 729 is 9.
2007-07-29 13:02:38 · answer #4 · answered by Tom K 6 · 0⤊ 0⤋
18
x = 2/3 * 27
2007-07-29 13:03:28 · answer #5 · answered by blizebliz 5 · 0⤊ 0⤋
x3/2=27
3x=27*2=54
x=54/3=18
2007-07-29 13:03:05 · answer #6 · answered by moona 4 · 0⤊ 0⤋
x3/2*2 =27*2
3x=54
3x/3=54/3
x=18
2007-07-29 12:59:14 · answer #7 · answered by Keith 6 · 0⤊ 0⤋
Multiply both sides by 2:
3x = 54 (always express with numbers first, times variables)
Divide both sides by 3:
X = 18
That's the answer.
2007-07-29 13:01:11 · answer #8 · answered by Richard B 4 · 0⤊ 0⤋
15x^4 - 28x^2 + 5 = 0 15x^4 - 28x^2 = -5 x^2 (15x^2 - 28) = -5 x^2 # -5 and 15x^2 - 28 = -5 15x^2 = -5 +28 15x^2 = 23 x^2 = 23/15 x = √ 23/15
2016-05-17 07:41:55 · answer #9 · answered by ? 3 · 0⤊ 0⤋
multiply both sides by 2
x3=27x2
to get to
x3=54
and divide both sides by 3
x=18
2007-07-29 13:00:27 · answer #10 · answered by nermil 5 · 0⤊ 0⤋