1. Dick spent $7 in order to buy baseballs and tennis balls. If baseballs are 70 cents each and tennis balls are 60 cents each, what is the greatest possible number of tennis balls that Dick could've brought? I just guessed and checked for this and got 7 but would like to know a algebraic way.
2. If the average of 4 #'s is 8000 and the average of 3 of the 4 numbers is 7500, then what must the 4th number be?
Thanks. If you could show the steps that'll be great.
2007-07-29 10:59:01 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
b = baseballs and t = tennis balls
so, 70b+60t = 700 --> 7b+6t = 70
Now if the problem requires that some baseballs must be purchased, and the entire $7.00 must be spent, then you have one equation with two unknowns. This can only be solved by trial and error. t = 7 and b = 4
(3*7500 + x)/4 = 8000
22,500 + x = 32000
x= 9500
2007-07-29 11:27:02 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋