What is log(8)64?

Question

What is the answer to this equation?

Answer 1

log (8) 64 = ?
8 is the base.
8 to what power = 64
8^2 = 64
Therfore log (8) 64 = 2

Answer 2

2

Answer 3

A=log(8)64
.
A=log(8)[ 8^2]
.
A=2 log(8)[8]
.
A=2 x 1
.
A=2
.

Answer 4

If the number in the parentheses is the base for the logarithm than the answer to this is 2.

Recall that if y=log(b)x then b^y=x. (In English the statement y=log(b)x is saying y is the exponent to which b must be raised to get x).

The question "What is log(8)64?" is therefore asking to what exponent must 8 be raised to get 64.

Thinking a bit more mathematically

Let x= log(8)64 then 8^x=64 which means x = 2.

Answer 5

2

Answer 6

According to the definition of logarithms:

8^2 = 64 -> log(8)64 = 2

Answer 7

Hey there!

You need to use the definition of a logarithm to solve the problem.

b^x=y is equivalent to log(base b)y=x

Here's the answer.

log(base 8)64 --> Write the problem.
log(base 8)64=x --> Set the above problem equal to x.
8^x=64 --> Use the definition of a logarithm.
8^x=8^2 --> Rewrite 64 as 8^2.
x=2 Use one to one property of exponents i.e. if b^x=b^y, then x=y.

So the answer is 2.

Hope it helps!

Answer 8

8² = 64 and thus
log 8 (64) = 2

Answer 9

log(8)64 is 2
It is the same thing as saying "8 raised to what power is equal to 64?". (Eight raised to the second power is 64.)

Hope this helps!

Answer 10

log(8)64=log(8)8^2=2log(8)8=2