Using Trigonometric Identites
help
2007-07-29 07:13:54 · 5 answers · asked by Bobby R 2 in Science & Mathematics ➔ Mathematics
1 - (sin^2)/(1 - cos)
(1- cos - sin^2) / (1 - cos)
Substitute, sin^2 + cos^2 = 1.
(sin^2 + cos^2 - cos - sin^2) / (1 - cos)
(cos^2 - cos) / (1 - cos)
-cos(1 - cos) / (1 - cos)
= -cos
2007-07-29 07:18:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1 - sin^2 / 1- cos
= cos^2 / 1- cos
This does not equal -cos. There seems to be an error in the problem.
2007-07-29 14:26:47 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
1 - sin²x/(1- cos x) = 1 - (1 - cos²x)/(1 - cos x) =
= 1 - (1 - cos x)(1 + cos x)/(1 - cos x) =
= 1 - (1 + cos x) = 1 - 1 - cos x = - cos x
2007-07-29 14:30:51 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
1- sin^2/(1-cos) = 1 - (1-cos^2)/(1-cos)
= 1 - (1+cos)(1-cos)/(1-cos)
= 1 - (1 + cos)
= -cos
2007-07-29 14:30:16 · answer #4 · answered by vlee1225 6 · 0⤊ 0⤋
Check to see if you copied the problem correctly.....
The way I see it is this....
1-sin^2 / ( 1-cos) = -Cos
Well 1-sin^2 = Cos^2 .........rewrite
Cos^2 / (1-Cos) = - Cos......... Multiply through by (1-Cos)
Cos^2 = - Cos ( 1-Cos)
Cos^2 = -Cos + Cos^2
Cos^2-Cos^2 = - Cos
0= -Cos No Way!!!!!!!!!
2007-07-29 15:04:40 · answer #5 · answered by ? 3 · 0⤊ 0⤋