solve by using the quadratic formula x2 - 3x = - 6x -1?

Answer 1

x² - 3x = - 6x -1

subtract - 6x -1 from both sides

x² + 3x +1 = 0

ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a

x = (-3 ± √(9 - 4))/2

x = (-3 ± √(5))/2
.

Answer 2

x² - 3x = - 6x - 1

Convert equation to standard form

Transpose 6x

x² - 3x + 6x = - 6x - 1 + 6x

collecting like terms

x² + 3x = - 1

Transpose 1

x² + 3x + 1 = - 1 + 1

x² + 3x + 1 = 0. . .Standard form

- - - - - - - -

Let

a = 1

b = 3

c = 1

- - - - - - - -

Quadratic Formula

x = - b ± √b² - 4ac / 2a

x = - 3 ± √(3)² - 4(1)(1) / 2(1)

x = - 3 ± √9 - 4 / 2

x = - 3 ± √5 / 2

x = - 3 ± 2.36067978 / 2

- - - - - - - -

Solving for +

x = - 3 + 2.236067978 / 2

x = - 0.763932023 / 2

x - 0.381966011

- - - - - - - - - -

Solving for -

x = - 3 - 2.236067978 / 2

x = - 5.236067978 / 2

x = - 2.618033989

- - - - - - - -s-

Answer 3

ok u have to first get everything on one side...................like the left side of the equation then u get
x2-3x+6x+1=0 solving that
x2+3x+1=0 (ax2+bx+c=0)
using the quadratic formula
-b+(-)sq rt(b2-4ac)/2a
then u get
-3+sq rt(5)/2 and -3 - sq rt(5)/2
hope u understood

Answer 4

You solve by using the quadratic formula. What do you think this is, grade school ??

You solve it, we're not gonna do it for you

Answer 5

no thank you. My religion forbids me to do math because math is the language of SATAN!!