solve by completing the square x^2 +6x +2 =0?

Answer 1

x² + 6x + 2 = 0

Transpose 2

x² + 6x + 2 - 2 = 0 - 2

x² + 6x = - 2

x² + 6x + ______ = - 2 + ______

x² + 6x + 9 = - 2 + 9

(x + 3)(x + 3 = 7

(x + 3)² = 7

(√x + 3) = ± √7

x + 3 = ± √7

Traspose 3

x + 3 - 3 = - 3 ± √7

x = - 3 ± √7

x = - 2 ± 2.645751311

- - - - - - - - -

Solving for +

x = - 3 + 2.645751311

x = - 0.354248689

- - - - - - - - -

solving for -

x = - 3 - 2.645751311

x = - 5.645751311

- - - - - - -s-

Answer 2

Hey there!

Here's the answer.

x^2+6x+2=0 --> Write the problem.
x^2+6x=-2 --> Subtract 2 on both sides of the equation.
x^2+6x+(6/2)^2=-2+(6/2)^2 --> Use completing the square. Add 6 to both sides of the equation. Divide 6 by 2 on both sides of the equation. Square the terms. In other words, if you have x^2+bx=c, completing the square should look like this x^2+bx+(b/2)^2=c+(b/2)^2.
x^2+6x+9=-2+9 --> Change (6/2)^2 into 9.
x^2+6x+9=7 --> Add -2 and 9.
(x+3)^2=7 --> Use the formula (a+b)^2=a^2+2ab+b^2.
x+3=±sqrt(7) --> Take the square root on both sides of the equation.
x=-3±sqrt(7) Subtract 3 on both sides of the equation.

So the answer is x=-3-sqrt(7) and x=-3+sqrt(7).

Hope it helps!

Answer 3

x^2 +6x +2 =0

Add 7 to both sides

x^2 +6x +9 = 7

(x + 3)² = 7

(x + 3) = ±√7

x = -3 ±√7
.

Answer 4

x^2 + 6x +9-9 +2 = 0
(x+3)^2 - 7=0
x+3=+(7)^1/2 or x+3=-(7)^1/2
x=-3+-(7)^1/2

Answer 5

x^2+6x+9-9+2
x^2+6x+9-7
(x+3)^2=7
x+3=sqrt7
x=(sqrt7)-3 or x= -[(sqrt7)+3]