A line passing through (10,4) and (-3,y) is perpendicular to a line with slope - 13/14. What is value of y?

Answer 1

Find the slope of the desired line... perpendicular to the slope given...

perpendicular m = the negative reciprocal of the slope given.
=(-14/13) I am not sure if the negative sign (hyphen) belongs to your slope, so your desired slope may be 14/3, instead of -14/13.

Then take (Y2-Y1)/(X2-X1) = m = -14/13

Solve for your Y2 value after plugging in all the information.

Answer 2

Ok, if one line has a slope of -13/14, then you switch the numerator and the denominator and multiply by -1 to get a line with a slope of 14/13, and those lines are perpendicular. :)

So a line with a slope of -1/2 and 2/1 would be perpendicular.

Now that you know the slope of the line passing through those points, you need to write an equation.

To find the slope of a line, you take one y (y2) minus the other y (y1) and divide that by x2 minus x1. Since we already know the slope of the line, we can do this.

If y2 is 4, and y1 is "y"
and x2 is 10 and x1 is -3, then we know that:

(4-y)/(10+3) = 14/13

So 4 minus what number equals 14?

4 - y = 14
(subtract 4 from each side)
-y = 10
(multiply each side by -1)
y = -10

Hope that helped. :)

Answer 3

slope of required line is 14/13

hence (4 - y)/(10 + 3) = 14/13
so y = -10 ...final answer

Answer 4

m = (y - 4) / (- 3 - 10)
m = (y - 4) / (- 13)
(- 13 / 14) [ (y - 4) / (- 13) ] = - 1
(y - 4) / 14 = - 1
y - 4 = - 14
y = - 10