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the radius of a sphere is increasing at a rate of 5cm/min. When the radius is 10cm, the rate of increase , in cm3(cube)/min, of the sphere is?

2007-07-29 02:42:36 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

V = 4/3*pi*r^3 so dV/dt= dV /dr*dr/dt = 4pir^2*dr/dt.
Ar the given point r=10 and dr/dt=5 so
dV/dt= 400*pi*5= 2000pi cm^3/min

2007-07-29 02:50:41 · answer #1 · answered by santmann2002 7 · 0 0

Maths is really a burden ....... i hate Maths ......

2007-07-29 09:47:41 · answer #2 · answered by Sweet teenager 2 · 0 0

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