2007-07-29 01:12:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x)/(x^2+2x-3) - (x)/(x^2-5x+4)?
= (x) / ((x+3)(x-1)) - (x) / ((x-4)(x-1))
= (x(x-4) - x(x+3)) / ((x+3)(x-1)(x-4))
= (x^2 - 4x - x^2 - 3x) / ((x+3)(x-1)(x-4))
= -(7x) / ((x+3)(x-1)(x-4))
= (-7x) / (x^3 - 2x^2 - 11x + 12)
2007-07-29 01:27:36 · answer #1 · answered by gudspeling 7 · 1⤊ 0⤋
x/[(x-3)(x+1)] - x/[(x-1)(x-4)]
[x^3 - 5x^2 + 4x - x^3 - 2x^2 + 3x] / (x-3)(x+1)(x-1)(x-4)
-7x / [(x-3)(x-1)(x-4)]
2007-07-29 01:36:47 · answer #2 · answered by Anonymous · 1⤊ 0⤋
23
2007-07-29 01:19:57 · answer #3 · answered by tentieooo 3 · 0⤊ 2⤋
x / (x + 3)(x - 1) - (x) / (x - 4) (x - 1)
[ x (x - 4) - x ((x + 3) ] / [ (x + 3) (x - 4) (x - 1) ]
[ - 7x ] / [ (x + 3) (x - 4) (x - 1) ]
2007-07-29 09:09:23 · answer #4 · answered by Como 7 · 0⤊ 0⤋