Determine the nature of roots of {x squared + 8x +16 = 0}?

Question

a. imaginary
b. real,irrational,unequal
c. real,rational,unequal
d. real,rational,equal

Answer 1

to know the nature of the roots, u have to calculate the Discriminant=(b squared-4ac) .If it is negative,the roots are imaginary.If it is zero,the roots are real,rational,equal.And if it is positive,the roots are real, unequal,could be either rational or irrational.If the discriminant is perfect square,or has a rational square root,then the roots are rational,but if the discriminant has an irrational square root,then the roots are irrational.
In our problem,
the discriminant= (b squared-4ac)
a=1 , b=8 , and c=16
disc.=64 - 4(1) (16) =0
therefore the roots are real,rational,equal.The answer is(d)

Answer 2

determine nature roots squared 8x 16 0

Answer 3

A few wrong answers here.

x^2+8x+16=0
so (x+4)(x+4)=0

so the roots are -4 and -4 which are real, rational, and equal
so (d)
.

Answer 4

(x squared + 8x + 16 = 0)
(x + 4)squared = 0
x=-4

D. real, rational, equal

Answer 5

x^2 + 8x + 16 is a perfect square, in fact
= (x + 4)(x+4)
so the root is -4, a real number

Answer 6

in this equation we check for the discriminant[D]
D=8^2-4*1*16=0
since D=0 the equation has equal real roots

Answer 7

b^2-4ac=(8)^2-4*1*16
=64-64
=0
Hence the roots are real,rational and equal

Answer 8

x=+4

real rational equal?

I havn't done algebra in a long time but that is my guess thought


oh and yah b^2+4ac=x^2+8x+16=0
(heh) Quadratics for that!!! come on people!!!

Answer 9

(x+4)^2=0 so
x+4=0
x=-4
d. real,rational,equal

Answer 10

Nature Of Roots