you have to prove it it is maths trignomatory question 2(Square)
2007-07-28 20:24:50 · 3 answers · asked by aryabhatt 1 in Science & Mathematics ➔ Mathematics
sinQ +cscQ =
sinQ(1 + csc^2Q) =
sinQ(1 + 1 + cot^2Q) =
sinQ(2 + cot^2Q)
sinQ +cscQ ≠ 2 + cot^2Q
2007-07-28 21:23:33 · answer #1 · answered by Helmut 7 · 1⤊ 1⤋
hey here it it
sinQ + cosecQ is L.H.S.(left hand side)
2+cot2Q is R.H.S(right hand side)
L.H.S.
sinQ + cosecQ
= sinQ + 1/sinQ (cosecQ = 1/sinQ)
= sin2Q + 1
=cos2Q(2 means square) ---------------1st equation
R.H.S
2+cot2Q
=1+1+cot2Q
=1+ cosec2Q (1+cot2Q = cosec2Q)
=1+ 1/sin2Q (cosec2Q = 1/sin2Q)
=sin2Q + 1
=cos2Q (sin2Q + 1=cos2Q)-------------2nd equation
both 1 and 2 are equal
hence it is proved that SinQ +cosecQ = 2+cot2Q
2007-07-29 03:49:37 · answer #2 · answered by pprr 2 · 1⤊ 1⤋
LHS and RHS not equal for every Q. do u want it to be solved?
2007-07-29 10:17:45 · answer #3 · answered by Anonymous · 1⤊ 0⤋