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i would i change these three expression into fractions

6a-4
------- -3
7a-5


y-1- 5
--------
y+3

y+ 2y^3
------------
x^3-y^3

2007-07-28 15:11:20 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Question 1
6a - 4 - 3(7a - 5)
---------------------
(7a - 5)

6a - 21a - 4 + 15
-------------------
(7a - 5)

- 15a + 11
-----------
7a - 5

Question 2
(y - 6) / (y + 3)

Question 3
y (2y² + 1) / (x³ - y³)

2007-08-01 14:20:39 · answer #1 · answered by Como 7 · 2 0

([6a - 4] / [7a - 5]) = 3
6a - 4 = 3(7a - 5)
6a - 4 = 21a - 15
15 - 4 = 21a - 6a
11 = 5a
11/5 = a

6(11/5) / 7(11/5) - 3
(66/5) / (77/5) - 3
6/7 - 3
- 2 1/7 or - 15/7 Answer

(y - 1 - 5) / (y + 3)
1 - 1/y - 5/y + y/3 - 1/3 - 5/3
- 1 - 6/y + y/3
y/3 = 1 + 6y
y = 3 + 18y
- 17/y = 3
- 17 = 3y
y = - 17/3

([- 17/3] - 6) / ([- 17/3] + 3)
(- 35/3) / (- 8/3)
- 35/3 * - 3/8
35/8 or 4 3/8 answer

2007-07-28 22:39:08 · answer #2 · answered by Jun Agruda 7 · 2 1

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