Math question needs answersings?

Question

On his fisrt test, Kurt scored 75, 82, 84. What must his score be on the fourth test for hic mean score to be 85?
46
24
99
109
Find the difference: 0.9 - 0.25
How many 1/2 inch stripes of ribbon can be cut from a piece of 7 inches log?
If a nickel, a dime,and a quarter are flipped at one time, how mant outcomes are possible?
give ya 10 points

Answer 1

99
0.65
14
8

Answer 2

1) 99
First you have to test out the numbers by adding 75 to 82 to 84 to one of the four choices. When you add the sum of the three original numbers to 46 you get a number lower than 85 so you cross that off and automatically cross off 24 because the mean score will be even lower. Then you test it out with 99 and it works.

2) .65
Think of question being 90-25 because basically it is. The actual question is .90-.25 or 90 hundredths minus 25 hundredths. So, you find the fina amount of 90-25 by doing basic subtraction. You get 65. But, since there were decimal points in the original question you put the decimal point in front of the 65 so it becomes .65.

3) 14
You need 2 half inch strips of ribbon to make 1 inch. So, you do 7 multiplied by 2.

4) 24
Each coin has two sides (heads and tails) and their are three of them. So it is 2 (sides) to the third (three coins) power. 2^3.
2 x 2 x 2=8
HHH, HHT, HTH, HTT, TTT, TTH, THT, THH

Answer 3

to find the average, add up add the numbers and divide by how many number there are

the averge is 85

85 = (75 + 82 + 84 + x)/4
340 = 241 + x
x = 99

so his fourth score must be 99



0.9 - 0.25 = 0.65


7/ (1/2) = 14 pieces

each coin has two ways to show its face: head or tail

since there are 3 dimes, use the principle of counting

2 x 2 x 2 = 8 ways

Answer 4

1. 99
2. .65
3. 14
4. 81

hope this helps!!

Answer 5

99
.65
14
6

Answer 6

1.99
2.0.35
3.14
4.6