if log(w)=.(1/5)log(x)-log(y), then w=?

5 ⤊

if log(w)=.(1/5)log(x)-log(y), then w=?

2007-07-28 11:54:02 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

log(w) = (1/5)log(x) - log(y)

Exponent rule for logs:
log(w) = log(x^(1/5)) - log(y)

Subtraction/division rule for logs:
log(w) = log[(x^(1/5)) / y]

So
w = (x^(1/5)) / y

2007-07-28 12:07:22 · answer #1 · answered by whitesox09 7 · 3⤊ 1⤋

log w = log x^(1/5) - log y
log w = log [ x^(1/5) / y ]
w = x^(1/5) / y

2007-08-01 15:18:49 · answer #2 · answered by Como 7 · 2⤊ 1⤋