how to simplify?

4 ⤊

((x)^(4B+1)) / ((X)^(2-B)

2007-07-28 11:52:13 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

x^{4B + 1 - 2 + B} = = x^{5B - 1}

2007-08-01 10:41:17 · answer #1 · answered by robert 6 · 1⤊ 0⤋

You use the rule for division of exponents:
x^a / x^b = x^(a-b)

Thus:

x^(4b+1) / x^(2-b) = x^(4b+1 - 2 + b) = x^(5b - 1)

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2007-07-28 12:05:34 · answer #2 · answered by G M 2 · 0⤊ 1⤋

to do that, recall the property that a^n/a^m = a^(n-m)o
say you have 3^100/3^98, then simplifying, we get
3^(100-98) = 3^2 = 9.
Similarly, x^(4B+1)/x^(2-B) = x^(4B+1-2+B)
=> =x^(5B-1).
there you go :D

2007-07-28 13:06:40 · answer #3 · answered by mikael 3 · 1⤊ 1⤋

x^(4B + 1 - 2 + B)
x^(5B - 1)

2007-08-01 08:16:17 · answer #4 · answered by Como 7 · 2⤊ 0⤋