how to factor this type of problem completely!!?

4 ⤊

484b^2 + 440b + 100

2007-07-28 11:23:30 · 4 answers · asked by whatever 1 in Science & Mathematics ➔ Mathematics

484b² + 440b + 100

= 4(121b² + 110b + 25)
= 4(11b + 5)(11b + 5)
= 4(11b + 5)²

2007-07-28 11:28:56 · answer #1 · answered by whitesox09 7 · 2⤊ 0⤋

484bÂ² + 440b + 100 = 4(121bÂ² + 110b + 25)
= 4(11b + 5)Â²

2007-08-01 12:20:46 · answer #2 · answered by Anonymous · 0⤊ 1⤋

4(121b^2 +110b +25)
4(11b+5)^2

2007-07-28 19:44:47 · answer #3 · answered by Grampedo 7 · 1⤊ 0⤋

4 (121bÂ² + 110b + 25)
4 (11b + 5) (11b + 5)
4 (11b + 5) Â²

2007-08-01 15:10:22 · answer #4 · answered by Como 7 · 1⤊ 1⤋