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(2x - 87) (x +5) = 0

Solve for x

2007-07-28 11:22:17 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Well it's already factored so just set each factor equal to 0.

(2x - 87) (x +5) = 0

2x - 87 = 0
2x = 87
x = 87/2

and

x + 5 = 0
x = -5

So x = -5 or 87/2. You can verify this by plugging the solutions back in.

2007-07-28 11:26:12 · answer #1 · answered by whitesox09 7 · 1 0

2x = 87
x = 87 / 2 , x = - 5

2007-08-01 15:07:56 · answer #2 · answered by Como 7 · 0 1

x = -5 and/or 87/2

2007-07-28 18:25:31 · answer #3 · answered by vslsub 2 · 0 0

(2x - 87) (x +5) = 0

Either:
2x = 87
x = 87/2

or
x + 5 = 0
x = -5.

2007-07-28 18:27:28 · answer #4 · answered by Anonymous · 0 0

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