1 word problem to ask?

Question

How do you calculate the molarities of the original HCl solutions,

18.00 mL of 0.555 M NaOH solution is titrated with 24.65 mL of HCl solution

-thnx

Answer 1

0.555molesNaOH/L x 0.01800L=9.99x10-3molesNaOH

When reacting NaOH and HCl it reacts in a 1 to 1 mole ratio therefore you have 9.99x10-3 molesHCl.

Therefore you have

9.99x10-3 molesHCl / 0.02465L = 2.46x10-4M HCl

Answer 2

Use this equation:

M1xV1 = M2xV2

where M = molarity and V = volume

NaOH = (18.00 mL) x (0.555 M)
NaCl = (24.65 mL) x (? M)

(18.00 mL) x (0.555 M) = (24.65 mL) x (unknown M)

(18.00 mL)(0.555 M) / (24.65 mL) = (unknown M)