10ab/c^3d divided by 15ab^3/7c^3d^4
(this is how it looked at the bottom but i didnt want to confuse anybody)
(10ab ) (15ab^3)
_____ / _______
(c^3d ) (7c^3d^4)
my answer also comes out to long
*its 4 empty spaces at the top and 3 at the bottom to fill ill*
2007-07-28 07:27:17 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
{(10ab)/(c^3d)}/{(15ab^3)/(7c^3d^4)}
or (10ab*7c^3d^4)/(c^3d*15ab^3)
or(70abc^3d^4/15ab^3c^3d)
(14*3^-1)*(b^-2.d^3)
2007-07-28 07:44:40 · answer #1 · answered by MAHAANIM07 4 · 0⤊ 0⤋
Just invert the second number and multiply:
(10ab/c^3d)(7c^3d^4/15ab^3) = 2d^3/3b^2
2007-07-28 07:38:43 · answer #2 · answered by jsardi56 7 · 0⤊ 1⤋
Division is really multiplication so just take the second part and flip it then cancel the like terms and multiply
2007-07-28 07:35:49 · answer #3 · answered by Love Exists? 6 · 0⤊ 0⤋
(10 a b)(7 c³ d^4)
---------------------
(c³ d ) (15a b³)
(70) b^(-2) d³
---------------
15
(14 d³ / 3 b²)
2007-08-01 06:43:43 · answer #4 · answered by Como 7 · 1⤊ 0⤋