math logs problem?

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If log w = 1/5 log x - log y, then w = ?

2007-07-28 06:55:32 · 6 answers · asked by Karina C. 2 in Science & Mathematics ➔ Mathematics

log w = log x^(1/5) - log y
log w = log [ x^(1/5) / y ]
w = x^(1/5) / y

2007-07-28 08:06:02 · answer #1 · answered by Como 7 · 0⤊ 0⤋

w=x^1/5 / y

2007-07-28 14:03:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋

log w = 1/5 log x - log y
log w = log x ^ (1/5) - log y
log w = log( x^(1/5) / y )
w = x^(1/5) / y

Hope this helps :)

2007-07-28 14:02:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋

log w = log (x^1/5) - log y
log w = log [(x^1/5)/y ]

w = (x^1/5)/y

2007-07-28 13:58:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋

w=(x^(1/5))/y

2007-07-28 14:01:02 · answer #5 · answered by solovus 1 · 0⤊ 0⤋

x^(1/5)/y

2007-07-28 13:59:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋