Can u help with this integral?

Question

Hi

Does anyone know how to integrate (sinx)^2?

Thanks

Answer 1

cos 2 x= cos ² x - sin ² x
cos 2 x = 1 - 2 sin ² x
2 sin ² x = 1 - cos 2 x
I = ∫ sin ² x = ∫ 1 / 2 - (1 / 2) cos 2 x dx
I = (1 / 2) x - (1 / 4) sin 2 x + C

Answer 2

First use this identity:

(sinx)^2 = (1/2)(1 - cos (2x))

and work with that:

INTEGRAL((1/2) (1 - cos (2x))) =

(1/2) (x - (1/2)Sin(2x)) + C

Answer 3

this is not syntax.
= + lose the ?.