Find the derivative of the function?

9 ⤊

1 y=ln(8+x^2)
2 y=(2x^2+3)ln(x+1)
3 y=ln 6x

2007-07-28 06:07:18 · 3 answers · asked by NECE 1 in Science & Mathematics ➔ Mathematics

1. y' = 2x/(8+x^2)
2. y' = 4xln(x+1) + (2x^2+3)/(x+1)
3. y' = 1/x

2007-07-28 06:18:42 · answer #1 · answered by sahsjing 7 · 4⤊ 0⤋

1 y=ln(8+x^2)
y' = 2x/(8+x^2)

2 y=(2x^2+3)ln(x+1)
y' =(2x^2+3)(1/(1+x) +2xln(x+1)
y' = (2x^2+3)/(1+x) + 2xln(x+1)

3 y=ln 6x
y' = 6/x

2007-07-28 13:26:35 · answer #2 · answered by ironduke8159 7 · 4⤊ 1⤋

1
y' = 2x/(8+x^2)

2
y' =(2x^2+3)(1/(1+x) +2xln(x+1)

3
y' = 6/x

2007-08-01 11:54:45 · answer #3 · answered by Anonymous · 1⤊ 2⤋