MATH HELP please!!!!?

Question

Hello, I am having a lot of trouble with patterns, can you help me please? This is for school and it's due soon I just can't figure it out. If you can, please post them and I will have so much less stress on my mind... thankyou!


Find the next two numbers in each pattern.
A) 4, 8, 12, 16, ______, _______
B) 3, 9, 27, 81, ______, _______
C) 144, 121, 100, 81, ______, _______
D) 3, -12, 48, -192, ______, _______
E) 7, 10, 14, 19, ______, _______
F) 2, 3, 7, 16, ______, _______

And then create an expression for the general term of each pattern.
(e.x. term n = (n) x (4) it's a sequence of numbers and it goes in order, term 1, term 2, term 3.... )

Answer 1

a) 20, 24
n x 4

b) 243, 729
3^n

c) 64, 49
I don't know but it's 12^2, 11^2, 10^2....

d) 768, -3072
I don't know but it's (last answer times -4)



YOU KNOW WHAT, I'M NOT DOING THIS FOR YOU ANYMORE!!! HAVE A NICE DAY JERK!!!!

Answer 2

a) 20 24 add 4 to the previous no.
b)243 729 multiply 3 to the previous no.
c)64 49 square of the no. 8 , 7, 6 ,...
d)768 -3072 multiply the previous no. by 4 and change the sign
e) 19+6 = 25 , 25+7 = 32, the first no. is added by 3, second by 4 and goes on
f) 65 321 the difference between 3 and 7 is 4 which is 2*2 , in the same way the difference between 16 and 7 is 9 which is 3*3 so the difference between 65 and 16 is 49 which is 7*7 and it goes on.

Answer 3

a) 20, 24; 4 x n where n = 1 to ∞
b) 243, 729; 3^n where n = 1 to ∞
c) 64, 49; n^2 where n = 12 to -∞
d) 768, 3072; 3 x 4^n x (-1)^n where n = 0 to ∞
e) 25, 32;
f) 32, 57;

Answer 4

A) 4, 8, 12, 16, ______, _______
20,24,28......4*n
B) 3, 9, 27, 81, ______, _______
243,729.........3^n
C) 144, 121, 100, 81, ______, _______
64, 49, 36, 25 ...... ( 13-n)^2 ( If n starts with 1 )
D) 3, -12, 48, -192, ______, _______
Simply like ..1*3, -4*3, 16*3, -64*3
Ans: 256*3, -1024*3 .... 4^n*3 ( let n >= 0 )
E) 7, 10, 14, 19, ______, _______
7, 7+3, 10+4, 14+5, 19+6, 25+7, ....... n+last_term
F) 2, 3, 7, 16, ______, _______
THIS is also similar Now u think .. ;)

Answer 5

A) 20, 24
x(n)= n x 4

B) 243, 729
x(n)= 3^n

C) 64, 49
x(n)= (-n + 13)^2

D) 768, -3072
x(n)= 3 x (-4)^(n-1)

E) 25, 32
x(1)=7, (n>1) x(n)= x(n-1)+n+1
7, 7+3, 7+3+4, 7+3+4+5,...

F) 32, 57
x(1)=2, (n>1) x(n)= x(n-1)+(n-1)^2
2, 2+1^2, 2+1^2+2^2, 2+1^2+2^2+3+2,...

Answer 6

A) 20, 24 term = 4*n
B) 243, 729 term = 3^n
C) 64, 49 term = (13-n)^2
D) 768, -3072 term = 3*(-4)^(n-1)
E) 25, 32 term = [(n+1)(n+2)]/2 + 4
F) 32, 57 term = [n(n-1)(2n-1)]/6 + 2

Answer 7

a) X(1)+4 = X(2)
4,8,12,16,20,24

b) X(1)*3 = X(2)
3,9,27,81,243,729

c) Sq Rt X(1) - 1 = Sq Rt X(2)
144,121,100,81,64,49

d) X(1)* -4 = X(2)
3,-12,48,-192,768,-3072

e) Not sure how to write this as a formula, but you add 3, then 4, then 5, then 6, etc
7,10,14,19,25,32

f) Not sure who to write this one either, but you are adding increasing perfect squares to the numbers (e.g. 2+1squared=3, 3+2 squared=7, 7+3squared=16, 16+4squared=32, 32+5squared=57
2,3,7,16,32,57

Answer 8

A) 20.24 [Last number +4=next number]
B)243,729 [Last number X3=Next number]
C)64,49[the numbers are squares of 12,11,10 and 9.Hence the next two numbers will be squares of 8 and 7 respectively]
D)768,-3072[last number multiplied by -4=next number]
E)25,32[7+3=10,10+4=14,14+5=19.Hence the next two numbers would be 19+6=25 and25+7=32]
F)

Answer 9

A) 20, 24 n=x*4
B)
C) 64, 49 n=x^2
D)
E) 25, 32
F)

Answer 10

A)20, 24
B)243, 729
C)64, 49
D)768, -3072
E)25, 32
F)32, 57

sorry i cant help with the expressions

Answer 11

a) 4,8,12,16,20,24,......., 4n.
b) 3,9,27,81, 243,729,........,3to the power n
c) 144,121,100,81,64,49,......,square of (13-n)
d) 3,-12,48,-192,768,-3072,........, 3*(4 to the power n-1)
e) 7, 10, 14, 19, 25, 32, ....., 7+ n(n+1)/2+1
f)2, 3, 7, 16, 32, 57, ........