2007-07-28 04:10:18 · 4 answers · asked by Imogen 1 in Science & Mathematics ➔ Mathematics
well d/dx ln (3x) = 1/(3x) * 3 = 1/x.chain rule..
2007-07-28 04:15:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
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RE:
when you differentiate ln(3x) do you just lose the 3 and get 1/x?
2015-08-18 13:46:58 · answer #2 · answered by Elwyn 1 · 0⤊ 0⤋
A simple way to look at this is to use the logarithm rules:
ln(3x) = ln(3)+ln(x)
Now you have the derivative of a constant, which is zero, plus the derivative of ln(x)
2007-07-28 04:17:39 · answer #3 · answered by Thomas M 6 · 2⤊ 1⤋
ln(3x)
product rule:
u= 3x f(u)=ln u
du=3 f'(u)=1/u
now, du*f'(u), evaluated at u, not x, gives
3*(1/(3x))= 3/3x, which simplifies to 1/x.
You don't really lose the three; it just simplifies out.
2007-07-28 08:41:11 · answer #4 · answered by james w 5 · 1⤊ 0⤋
kind of. ln(3x) = ln(3) + ln(x) so the first term is a constant and when you differentiate a constant you get 0
2007-07-28 04:17:35 · answer #5 · answered by Captain Mephisto 7 · 2⤊ 1⤋
After differentiating it, u will get 3/3x.
From there, u will then simplify it into 1/x.
Hope this will help u.
2007-07-28 04:17:46 · answer #6 · answered by lhcom6 1 · 0⤊ 1⤋