What is the best way to solve (x-2)^2=20?

Answer 1

(x-2)^2=20

take square root of both sides (x^.5 is squart root of x)

(x-2) = +/-(20)^.5 = +/-(4 x 5) ^.5 = +/-2 (5)^.5

add 2 to both sides...

x = +/-2(5)^.5 + 2 = 2 +/- 2(5)^.5

so x = 2 ( 1+5^.5)
and x = 2 (1- 5^.5)

Answer 2

Hey there!

Here's the answer.

(x-2)^2=20 --> Write the problem.
x-2=±sqrt(20) --> Take the square root on each side of the equation.
x=2±sqrt(20) Add 2 to both sides of the equation.

So the answer is x=2±sqrt(20) or x=2±2sqrt(5).

Hope it helps!

Answer 3

Depends if you r allowed to use calculators.cause in some exams students r.. lol..if not simply expand th left hand side and make it a quadratic equation and solve for the roots.with calculator..take square root on both sides and then add 2 to ur answer..plz take care of the negative sign off the sqyare root.

Answer 4

Take the square root of both sides. Then:
x-2=+/- sqrt(20)
Then add 2:

x= 2+/-sqrt(20)

Answer 5

(x - 2) = ±√20
(x - 2) = ± 2 √5
x = 2 ± 2√5
x = 2 (1 ± √5) gives exact answers.
If desired, √5 may be calculated to give approximate answers.

Answer 6

(x-2)^2=20

square root both sides and solve it. because after you square root the (x-2)^2, the ^2 eventually 'dies'. so, this makes it easier to get 'x'.

i hope it helps.
=)

Answer 7

(x-2)^2=20
(x-2)=+/- rt20=+/- 2 sqrt5
x=2+/-2sqrt5

Answer 8

blow a nerd. they will do anything for you