Solve the triangle if angle B = 45 degrees, angle c = 95 degrees and side AB = 5 units. Use the law of sines.
2007-07-28 02:55:12 · 9 answers · asked by journey 1 in Science & Mathematics ➔ Mathematics
frm law of sines,sin C/c=sin B/b.now b=5
angle A=180-(95+45)=40 degrees.
u can find c by the first equation and can then easily find a frm law of sine.jst try.
2007-07-28 03:02:51 · answer #1 · answered by aviral17 3 · 1⤊ 0⤋
If one angle is 45, and the other is 95, the remaining angle is only 40 degrees.
The law of sines only works with right triangles... and there are no right angles there... Unless you meant angle C to be 90 degrees, not 95:
Then the hypotenuse (AB) would be 5 and the legs (AC and CB) would be both the square root of 5. Angles A and B would be 45 degrees.
That's if you made a typo...
~dream
2007-07-28 03:07:11 · answer #2 · answered by Lena 2 · 0⤊ 1⤋
Well first angle A = 180- (45+95) = 40
Using the law of sines:
(AC/sin B) = (AB/sin C) or AC = 5* (sin 45/sin95) = 3.55
(BC/sin A) = (AB/sin C) or BC = 5* (sin 40/sin 95) = 3.23
2007-07-28 03:07:44 · answer #3 · answered by dr_no4458 4 · 1⤊ 0⤋
The triangle may well be built as follows: -start up with 2 rays with an issue-unfastened beginning place and an perspective seventy 5° between them. Label the beginning place B -diploma 8 centimetres (the actual scale isn't given, so we are able to choose the unit) alongside between the rays. Label the factor A so as that the sting c is opposite the vertex C. -Create a circle around A with a radius 6 cm. -Intersect the circle with the 2d ray. --If there are 2 intersections, label them C_1 and C_2 --If there is one intersection, label it C --If there is not any intersection, no answer exists. appearing the form shows the is not any answer.
2016-10-09 12:00:50 · answer #4 · answered by larusch 3 · 0⤊ 0⤋
Well if a triangle is 180 degrees, the angle of A would be 40 degrees.
It's been a while so I can't see the "units"
2007-07-28 03:04:48 · answer #5 · answered by Colonel 6 · 0⤊ 1⤋
Why you don't use the law of sines as recommended?
It is here:
http://hyperphysics.phy-astr.gsu.edu/hbase/lsin.html
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To dream:
The law of sines works for ANY triangle.
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2007-07-28 03:03:27 · answer #6 · answered by oregfiu 7 · 0⤊ 0⤋
sin(95)/5 = sin(45)/(AC)
AC = sin(45)/(sin(95)/5)
AC = about 3.55
sin(95)/5 = sin(40)/(BC)
BC = sin(40)/(sin(95)/5)
BC = about 3.23
Angle A = 40
AC = about 3.55 units
BC = about 3.23 units
2007-07-28 03:59:43 · answer #7 · answered by Sherman81 6 · 1⤊ 0⤋
U don't know ? ? ? Use ur own mind....
2007-07-28 02:59:25 · answer #8 · answered by Anonymous · 1⤊ 0⤋
I dont know...!!!!
2007-07-28 02:58:04 · answer #9 · answered by tabitoe 2 · 0⤊ 1⤋