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2007-07-27 16:44:54 · 4 answers · asked by matcav2002 1 in Science & Mathematics Mathematics

Number problems. Find two consecutive positive integers such that the sum of 85?

2007-07-27 17:18:32 · update #1

4 answers

let us first assign variables for conveience.
let:
x= first positive integer
since the second positive integer is simply 1 more than the first (i.e. 3 is just 1+ 2, 10 is just 1 + 9, they are consecutive)
x + 1 = second positive integer

using your given sum:
(1st) + (2nd) = 85
substituting our variables:
(x) + (x+1) = 85
x + x + 1 = 85 (associativity)
2x +1 = 85
2x = 85-1 (transposition)
2x = 84 (subtraction)
x = 42 (dividing both sides by 2)

x=42 => ist positive integer
x + 1 = 42 + 1
x+1 = 43 => 2nd positive integer


the two consecutive postive integers are 42 and 43.

to check:
1st + 2nd = 85
42 + 43 = 85
85 = 85
=)

2007-07-27 21:51:31 · answer #1 · answered by dy_fgg 1 · 0 0

Let X be a positive integer and X+1 the consecutive positive integer.
The sum will be X + X + 1 = desired number
X = (desired number -1) / 2

2007-07-27 16:50:44 · answer #2 · answered by skipper 7 · 0 1

n + n + 1 = 85
2n = 84
n = 42
n + 1 = 43
42 + 43 = 85

2007-07-27 17:38:27 · answer #3 · answered by Helmut 7 · 1 0

Are you looking for sample problems of this sort? Your question is not complete.

2007-07-27 16:49:25 · answer #4 · answered by Anonymous · 0 1

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