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GIVEN:AB and CD intersect at E, BA bisects CD, CA_I_CD, BD_I_ CD
PROVE:a. [triangle]ACE~=[triangle]BDE. b. AE~=BE

2007-07-27 11:49:58 · 1 answers · asked by Mike Gaol 1 in Science & Mathematics Mathematics

1 answers

AC_|_ CD and BD_|_ CD { Given}
Therfore angle C = angle angle D {All right angles are =}
angle AEC = angle DEB {vertical angles are =}
BA bisects CD {Given}
Therefore CE = ED {Definition of bisector}
Therefore triangle ACE congruent triangle BDE {ASA)
Q.E.D

2007-07-27 12:10:16 · answer #1 · answered by ironduke8159 7 · 0 0

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