Perform the indicated operation. Simplify if possible.
9y^2 / y - 1 + - 9y / y - 1
9y / y - 1
9y( 9 y + 1 ) / y - 1
9y
0
2007-07-27 10:47:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
9y - 1 - 9 - 1 = 9y - 11
9 - 1 = 8
(81y^2 + 9y)/y - 1 = 81y + 9 - 1 = 81y + 8
9y
0
2007-07-27 10:51:45 · answer #1 · answered by Becky M 4 · 0⤊ 1⤋
(9y^2 - 9y) / y - 1 =
9y (y -1) / y -1 =
9y
9y / y - 1 is in simplest form
9y (9y + 1) / y + 1 is in simplest form
81y^2 + 9y / y + 1 is this distributed out
9y as a monomial is in simplest form
0 is in simplest form
2007-07-27 18:01:06 · answer #2 · answered by Don E Knows 6 · 0⤊ 0⤋
9y^2/y - 1 + - 9y/y - 1 =
9y -1 -9 -1 =
9y - 11
If the original equation = 0, then
9y -11 = 0
9y = 11
y = 11/9
2007-07-27 17:53:51 · answer #3 · answered by robertonereo 4 · 0⤊ 1⤋
9y^2 /( y - 1) + (- 9y) /( y - 1) <-- I think this what you meant
= (9y^2 -9y )/ (y-1)
= 9(y-1)/(y-1)
= 9
You said this problem which to me means one problem.
9y and 0 are certainly not problems; nor are they answers.
2007-07-27 18:03:49 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋
9y^2/y-1 + -9y/y-1
(9y^2 - 9y )/y-1
9(y^2 - y)/y-1
9y(y-1)/(y-1)
9y
2007-07-27 17:53:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋