How do you do this problem ?

Question

Perform the indicated operation. Simplify if possible.
2^x / x ^2 - 7x + 12 - 8 / x^2 - 7x + 12

2 / x - 3

2 / x - 4

2 ( x + 4 ) / ( x - 4) ( x - 3 )

2 ( x - 4 ) / (x + 4 ) ( x - 3 )

Answer 1

Reading as:-
2x (x² - 7x + 12) - 8 / (x² - 7x + 12):-
(2x - 8) / (x² - 7x + 12)
2(x - 4) / (x - 4) (x - 3)
2 / (x - 3)

Answer 2

The way you have this question layed out doesn't help!
As written it would 2^(x-3)/x^2
or if it was 2^x / (x ^2 - 7x + 12) - 8 / (x^2 - 7x + 12)
it'd be 2^(x-3)/((x + 4 )*( x - 3 ))

Answer 3

2^x/x^2 - 7x + 12 - 8/x^2 - 7x + 12 =
(2^x - 8)/x^2 - 14x + 24 =
2{[(2^(x-1) - 4]/x^2 - 7x + 12}