2007-07-27 09:12:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(m^2 / n^3)
= sqrt(m^2 n / n^4)
= m sqrt(n) / n^2.
2007-07-27 09:16:20 · answer #1 · answered by Anonymous · 0⤊ 1⤋
m/n*sqrt(1/n)
Remember that square roots can be broken apart. So the sqrt(m^2/n^3) is really just sqrt(m^2)*sqrt(1/n^2)*sqrt(1/n)
The square roots of the first two terms should be obvious. Simplifying, you get (m)*(1/n)*sqrt(1/n). Combining the first two terms gives you (m/n)*sqrt(1/n), and you're done.
2007-07-27 09:19:27 · answer #2 · answered by Jonny Jo 3 · 0⤊ 0⤋
(m² / n³)^(1/2) = m / n^(3/2)
2007-07-27 11:29:25 · answer #3 · answered by Como 7 · 0⤊ 0⤋
break it up:
sqrt(m^2) = m
----------------------
sqrt(n^3) = n^3/2
m/(n^3/2) can be written as m * n^-(2/3)
2007-07-27 09:17:04 · answer #4 · answered by miggitymaggz 5 · 0⤊ 0⤋