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Evaluate:

x - y
------------
z to the 3rd power

when:
x = 3/4
y = 3/8
z = 1/2

2007-07-27 08:44:26 · 11 answers · asked by L. ♥. V. E. 2 in Science & Mathematics Mathematics

11 answers

Start...

3/4 - 3/8
---------
(1/2)^3


Convert top fractions to use lowest-common-demoninator...

6/8 - 3/8
---------
(1/2)^3


Subract the top fractions...

3/8
---------
(1/2)^3


Handle the exponent on the bottom (1/2 to the 3rd power is 1/8)...

3/8
---------
1/8

Divide the two fractions...

3/1


3 divided by 1 is 3...

3


There you go!

2007-07-27 08:52:25 · answer #1 · answered by Anonymous · 0 0

the first thing you need to do is to expand the denominator to get rid the 3rd power: (1/2)(1/2)(1/2) = 1/8 . Now, put them in to similar fractions, specifically: find a common denominator, which is 8.
now rewrite the eqn with these common fractions:

x = 6/8
y = 3/8
z = 1/8

therefore you will have:

[(6/8) - (3/8)]/((1/8)

first, combine the numerator: (6/8) - (3/8) = 3/8

now you have:

(3/8)/(1/8)

whenever you have a fraction over a fraction, you can multiply the top and bottom by the reciprocal of the bottom, which is simply flipping the numerator and denominator; here = 8/1

so your denominator will be: (1/8)*(8/1) = 1/1 = 1 -- and can be neglected.

your numerator will be: (3/8)*(8/1) = 24/8 = 3.

ANS: = 3

2007-07-27 08:54:45 · answer #2 · answered by miggitymaggz 5 · 0 0

It is not tricky; you have yet to master simple fractions; I answered one for you earlier - frankly the type of problem I masterd back in 5th grade. To divide a fraction, invert the denominator and multiply

[(3/4) - (3/8)]/ (1/2)^3 =
[3/4-3/8] * 2^3 =
[3/4 - 3/8] * 8 =
[6/8 - 3/8] *8 =
[6-3] * 8/8 =
6-3

2007-07-27 08:51:33 · answer #3 · answered by GTB 7 · 0 0

3/4-3/8=3/8
1/2 to the third power=1/8
3/8 over 1/8 is equal to 3/8 * 8, which means the answer is 3.

2007-07-27 08:52:33 · answer #4 · answered by Jenniferr. 2 · 0 0

3/8 divided by 1/8

=3

2007-07-27 08:50:38 · answer #5 · answered by rosie recipe 7 · 0 0

(x - y) / z^3

(3/4 - 3/8) / (1/2)^3

First cube the 1/2:
= (3/4 - 3/8) / (1/8)

Now make a common denominator of 8:
= (6/8 - 3/8) / (1/8)
= (3/8) / (1/8)

Reverse the denominator and multiply:
= (3/8) * (8/1)

Multiply the fractions:
= (3*8) / (8*1)

Divide numerator and denominator by 8:
= 3

2007-07-27 08:47:53 · answer #6 · answered by whitesox09 7 · 1 0

If you mean

(x-y)/(z^3),
just plug the values in and the numerical answer will pop right out.
(1/2)^3 = (1/8),
x-y = (3/4)-(3/8) = (3/8),
and (3/8)/(1/8) = 8*(3/8) = 3.

2007-07-27 08:48:36 · answer #7 · answered by Not Eddie Money 3 · 0 0

((3/4) - (3/8)) / (1/2)^3
((6/8) - (3/8)) / (1/8)
3/8 / 1/8
(3/8)(8/1)=3

2007-07-27 08:50:26 · answer #8 · answered by skipper 7 · 0 0

this is really easy. you need to know fractions! 3/4 - 3/8 = 3/8
1/2^3 = 1/8
so -3/8 over 1/8 = 3

2007-07-27 08:48:54 · answer #9 · answered by Jen B 2 · 0 2

(x-y)/z^3
(3/4-3/8)/(1/2)^3
or (3/8)/(1/8)
or 3 ans

2007-07-27 08:49:06 · answer #10 · answered by MAHAANIM07 4 · 0 0

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